Question

7.7a contrast situations where work is done with erent amounts of force to situations where no work is done such as moving a box with a ramp and without a ramp, or standing still
work
work is the amount of force applied times the distance over which it is applied. in order for work to occur or happen... the object must move in the direction of the force applied.
work = force x distance w = f x d
solve:

1. a force of 625 n is needed to push a car across a lot. two student push the car 35 m. how much work is done?
2. you push against the wall for 3min with a force of 10 n. how much work is done? explain.

Explanation:

Step1: Identify the formula

Work formula is \(W = f\times d\)

Step2: Solve problem 1

Given \(f = 625\ N\) and \(d=35\ m\). Substitute into formula: \(W=625\times35 = 21875\ J\)

Step3: Analyze problem 2

For work to occur, the object must move in the direction of the force. When pushing a wall, the wall does not move. So \(d = 0\ m\). Using \(W=f\times d\), with \(f = 10\ N\) and \(d = 0\ m\), \(W=10\times0=0\ J\)

Answer:

1. \(21875\ J\)
2. \(0\ J\) (because the wall does not move, so \(d = 0\) and \(W=f\times d=10\times0 = 0\))