Question

a 70 n force is applied to a 35 kg object. the same force is applied to a 20 kg object. how do the accelerations of the two objects compare? 70 n = 35 kg (a) 70 n = 20 kg (a) both objects will have the same acceleration. the 20 kg object will have smaller acceleration. the 20 kg object will have greater acceleration.

Explanation:

Step1: Calculate acceleration for 35 kg object

Using Newton's second law \(F = ma\), so \(a=\frac{F}{m}\). For \(m = 35\space kg\) and \(F=70\space N\), \(a_1=\frac{70}{35}=2\space m/s^{2}\)

Step2: Calculate acceleration for 20 kg object

Using \(a=\frac{F}{m}\). For \(m = 20\space kg\) and \(F = 70\space N\), \(a_2=\frac{70}{20}=3.5\space m/s^{2}\)

Step3: Compare the accelerations

Since \(3.5>2\), the 20 - kg object has a greater acceleration.

Answer:

The 20 kg object will have greater acceleration.