Question

a 600 kg roller coaster car is at the top of a hill. when it goes down, the net force is 3,000 n. what is the acceleration of the car?
2 m/s²
20 m/s²
5 m/s²
0.2 m/s²

Explanation:

Step1: Recall Newton's second law

$F = ma$, where $F$ is force, $m$ is mass and $a$ is acceleration. We need to solve for $a$.

Step2: Rearrange the formula for acceleration

$a=\frac{F}{m}$

Step3: Substitute given values

Given $F = 3000N$ and $m = 600kg$, then $a=\frac{3000}{600}$
$a = 5m/s^{2}$

Answer:

C. $5m/s^{2}$