Question

a 6.50 m high cylinder is filled with alcohol (density = 806 kg/m^3). what is the pressure at the bottom of the cylinder? (unit = pa) (1 atm = 101300 pa)

Explanation:

Step1: Recall the formula for pressure in a fluid column

The formula for pressure \( P\) at a depth \( h\) in a fluid of density \(
ho\) is \( P=
ho gh\), where \( g = 9.8\space m/s^{2}\) is the acceleration due to gravity.

Step2: Substitute the given values into the formula

Given \(
ho=806\space kg/m^{3}\), \( h = 6.50\space m\), and \( g=9.8\space m/s^{2}\).

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First, calculate \( 806\times9.8 = 7898.8\).
Then, \( 7898.8\times6.50=51342.2\space Pa\)

Answer:

\( 51342.2\space Pa\)