Question

a 0.289 kg bat is flying 4.25 m/s. it then doubles its velocity.
how much kinetic energy did it gain?
\\(ke = ?\\) j

Explanation:

⚡ Using what you learned: kinetic energy and the work-energy theorem

Step 1: Identify initial and final velocities

$$ v_i = 4.25\text{ m/s} $$

$$ v_f = 2 \times 4.25\text{ m/s} = 8.5\text{ m/s} $$

Step 2: Calculate initial kinetic energy

$$ KE_i = \frac{1}{2} m v_i^2 = \frac{1}{2} (0.289\text{ kg}) (4.25\text{ m/s})^2 \approx 2.6101\text{ J} $$

Step 3: Calculate final kinetic energy

$$ KE_f = \frac{1}{2} m v_f^2 = \frac{1}{2} (0.289\text{ kg}) (8.5\text{ m/s})^2 \approx 10.4404\text{ J} $$

Step 4: Calculate the kinetic energy gained

$$ \Delta KE = KE_f - KE_i = 10.4404\text{ J} - 2.6101\text{ J} \approx 7.83\text{ J} $$

Answer:

7.83