Question

1. each crate has a pair of forces acting on it. which crate will have the greatest acceleration? (f=ma)

Explanation:

Step1: Analyze the first crate (mass unknown)

Net force \( F_{net1} = 25N - 20N = 5N \). But mass is unknown, so we can't calculate acceleration yet.

Step2: Analyze the second crate (15 kg)

Net force \( F_{net2} = 28N - 20N = 8N \).
Using \( F = ma \), acceleration \( a_2 = \frac{F_{net2}}{m_2} = \frac{8N}{15kg} \approx 0.53 \, m/s^2 \).

Step3: Analyze the third crate (10 kg)

Net force \( F_{net3} = 40N - 25N = 15N \).
Acceleration \( a_3 = \frac{F_{net3}}{m_3} = \frac{15N}{10kg} = 1.5 \, m/s^2 \).

Step4: Analyze the fourth crate (15 kg)

Net force \( F_{net4} = 40N - 25N = 15N \).
Acceleration \( a_4 = \frac{F_{net4}}{m_4} = \frac{15N}{15kg} = 1 \, m/s^2 \).

Step5: Compare accelerations

• \( a_2 \approx 0.53 \, m/s^2 \)
• \( a_3 = 1.5 \, m/s^2 \)
• \( a_4 = 1 \, m/s^2 \)

The first crate’s mass is unknown, but among the others, \( a_3 \) is the largest.

Answer:

The crate with 40 N (right), 25 N (left), and mass 10 kg (the third option) will have the greatest acceleration.