Question

1. a 0.09 kg beetle climbs vertically a distance of 0.35 m up a wall at a speed of 0.02 m/s. what is the beetles power output? (1 point) 0.3087 w 15.44 w 0.006174 a 0.01764 w

Explanation:

Step1: Calculate the force

The force \(F\) is equal to the weight of the beetle. Using \(F = mg\) (where \(m = 0.09\space kg\) and \(g= 9.8\space m/s^{2}\)).
\(F=0.09\times9.8 = 0.882\space N\)

Step2: Use the power formula \(P = Fv\)

Given \(v = 0.02\space m/s\) and \(F = 0.882\space N\)
\(P=0.882\times0.02\)
\(P = 0.01764\space W\)

Answer:

0.01764 W