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Question
- at what point is the comet going to experience the greatest gravitational force and tangential velocity? why?
- which of the following graphs accurately shows the force of gravity vs mass?
- which of the following graphs accurately shows the force of gravity vs distance from the center?
- two students are sitting 1.5 m apart. one student has a mass of 70 kg and the other has a mass of 52 kg. what is the gravitational force between them (dont forget about g!!!!!)?
- what gravitational force does the moon produce on the earth if their centers are 3.84 x 10⁸ m apart and the moon has a mass of 7.36 x 10²² kg? (hint: the mass of the earth is on your formula chart.)
Question 16 Solution:
Step1: Recall the gravitational force formula
The formula for gravitational force between two objects is $F = G\frac{m_1m_2}{r^2}$, where $G = 6.674\times 10^{-11}\ \text{N·m}^2/\text{kg}^2$, $m_1$ and $m_2$ are the masses of the two objects, and $r$ is the distance between their centers.
Step2: Identify the given values
Here, $m_1 = 70\ \text{kg}$, $m_2 = 52\ \text{kg}$, and $r = 1.5\ \text{m}$.
Step3: Substitute the values into the formula
First, calculate the product of the masses: $m_1m_2 = 70\times52 = 3640\ \text{kg}^2$.
Then, calculate $r^2 = (1.5)^2 = 2.25\ \text{m}^2$.
Now, substitute into the formula:
$F = 6.674\times 10^{-11}\times\frac{3640}{2.25}$
First, compute $\frac{3640}{2.25}\approx 1617.78$.
Then, multiply by $G$: $F = 6.674\times 10^{-11}\times1617.78\approx 1.03\times 10^{-7}\ \text{N}$.
Question 14 Explanation (Graph Identification):
The gravitational force $F$ on an object near the Earth's surface is given by $F = mg$, where $g$ is the acceleration due to gravity (a constant). This is a linear relationship ($F\propto m$), so the graph of force vs mass should be a straight line with a positive slope (as mass increases, force increases) and passing through the origin (when mass is 0, force is 0). Graph A shows this linear, directly proportional relationship, while B shows a negative slope, and C and D show non - linear relationships, which do not match $F = mg$.
Question 15 Explanation (Graph Identification):
The gravitational force formula is $F = G\frac{Mm}{r^2}$, which shows that the force is inversely proportional to the square of the distance ($F\propto\frac{1}{r^2}$). This is a non - linear relationship (inverse - square law). Graphs A (positive linear) and B (negative linear) show linear relationships, which are incorrect. Graph C shows a curve that does not match the inverse - square behavior, while Graph D shows a curve where force decreases rapidly as distance increases, consistent with $F\propto\frac{1}{r^2}$.
Question 13 Explanation:
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$\boldsymbol{1.03\times 10^{-7}\ \text{N}}$ (approximate value, depending on $G = 6.674\times 10^{-11}\ \text{N·m}^2/\text{kg}^2$)