Question

a 1250 kg car traveling at 15 m/s comes to a complete stop in 5 seconds. what is the magnitude of the braking force?

Explanation:

Step1: Calculate acceleration

Use the formula \(a=\frac{v - u}{t}\), where \(u = 15\ m/s\), \(v=0\ m/s\), \(t = 5\ s\).
\(a=\frac{0 - 15}{5}=- 3\ m/s^{2}\) (negative sign indicates deceleration)

Step2: Calculate braking force

Use Newton's second law \(F = ma\), where \(m = 1250\ kg\), \(a=3\ m/s^{2}\) (magnitude of acceleration)
\(F=1250\times3 = 3750\ N\)

Answer:

\(3750\ N\)