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Question
a 12 kg object experiences a net force of 120 n. what acceleration will this object experience?
Step1: Recall Newton's second law
Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration.
Step2: Solve for acceleration
We need to find \(a\), so we can rearrange the formula to \(a=\frac{F}{m}\). Given \(F = 120\space N\) and \(m=12\space kg\), then \(a=\frac{120}{12}\).
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\(10\space m/s^{2}\)