Question

1. an electrical device draws 2 a of current at 120 v. how much power does it use?

60 w 122 w 240 w 1200 w

1. the most important factor affecting the ease of current flow is the _.

diameter of the conductor length of the conductor
temperature type of material

1. a material with a resistance of 0.001 ω would be classified as a _.

conductor insulator semiconductor superconductor

1. which of the following statements is not true?

metals are good conductors because their outer electrons can be moved easily.
resistance can be considered electrical friction.
some materials become superconductors when they are heated.
some semiconductors allow current to flow in one direction only.

1. which of the following statements regarding ohms law is not true?

the formula for ohms law is v = ir.
if the voltage is increased, the current also increases.
if the voltage is constant and the current decreases, the resistance also decreases.
a resistor added to a circuit can protect delicate electrical components.

1. which of these is required for an electric current to flow through a circuit properly?

a load a resistor a switch a versorium

1. a _ consists of a narrow strip of metal housed in a protective, insulated case.

circuit breaker ground fuse resistor

1. the _ is the work per unit charge; it is the \pressure\ with which an electric current flows.

amppere coulomb voltage wattage

1. in a(n) _ circuit, the current flows through all the loads simultaneously.

open parallel series short

1. a series circuit powered by a 9v battery has four loads, each with a resistance of 12 ω. what is the total resistance?

4 ω 12 ω 36 ω 48 ω

Explanation:

Step1: Recall the power formula

The formula for power is \(P = VI\), where \(P\) is power, \(V\) is voltage, and \(I\) is current.

Step2: Substitute the given values

Given \(V = 120\space V\) and \(I=2\space A\), substitute into the formula: \(P=(120\space V)\times(2\space A)\)

Step3: Calculate the power

\(P = 240\space W\)

Answer:

240 W