Question

a 10 kg sled is pulled across a flat, icy surface. the normal force (fn) on the sled is 80.0 n, and the coefficient of kinetic friction (μ) is 0.28. what is the magnitude of the friction force (ff)? ff = μ x fn

Explanation:

Step1: Recall the formula for kinetic friction force

The formula for kinetic friction force is \( F_f=\mu\times F_N \), where \( \mu \) is the coefficient of kinetic friction and \( F_N \) is the normal force.

Step2: Substitute the given values into the formula

Given \( \mu = 0.28 \) and \( F_N=80.0\ N \).
Substitute these values into the formula: \( F_f = 0.28\times80.0\ N \).

Step3: Calculate the value of \( F_f \)

\( F_f=0.28\times80.0 = 22.4\ N \)

Answer:

\( 22.4\ N \)