Question

1. determine a trans - former has 300 loops in the primary coil and 100 loops in the secondary coil. the primary coil voltage is 90 v. what would be the voltage in the secondary coil? what kind of transformer is this?

Explanation:

Step1: Recall the transformer voltage ratio formula

The formula for a transformer is $\frac{V_p}{V_s}=\frac{N_p}{N_s}$, where $V_p$ is the primary voltage, $V_s$ is the secondary voltage, $N_p$ is the number of primary - coil loops, and $N_s$ is the number of secondary - coil loops.

Step2: Substitute the given values into the formula

We are given that $N_p = 300$, $N_s=100$, and $V_p = 90$ V. Substituting into $\frac{V_p}{V_s}=\frac{N_p}{N_s}$, we get $\frac{90}{V_s}=\frac{300}{100}$.

Step3: Solve for $V_s$

Cross - multiply: $300V_s=90\times100$. Then $V_s=\frac{90\times100}{300}$. Simplifying, $V_s = 30$ V.

Step4: Determine the type of transformer

Since $N_p>N_s$ (300 > 100) and $V_p>V_s$ (90 V>30 V), this is a step - down transformer.

Answer:

The voltage in the secondary coil is 30 V. This is a step - down transformer.