Question

5.00 l gas sample at 85 kpa is compressed to 3.50 l. find the new pressure.

Explanation:

Step1: Write down Boyle's Law formula

Boyle's Law states that \( P_1V_1 = P_2V_2\) (for a gas at constant temperature, where \(P\) is pressure and \(V\) is volume).

Step2: Identify the known values

We have \(P_1 = 85\space kPa\), \(V_1=5.00\space L\), and \(V_2 = 3.50\space L\). We need to find \(P_2\).

Step3: Rearrange the formula to solve for \(P_2\)

From \(P_1V_1 = P_2V_2\), we can get \(P_2=\frac{P_1V_1}{V_2}\)

Step4: Substitute the values into the formula

\(P_2=\frac{85\space kPa\times5.00\space L}{3.50\space L}\)
\(P_2=\frac{425}{3.50}\space kPa\)
\(P_2\approx121\space kPa\)

Answer:

The new pressure is approximately \(121\space kPa\)