Question

1. you mix lead (ii) nitrate solution with calcium bromide solution. write the balanced chemical equation, complete ionic equation, and net ionic equation for this reaction.

Explanation:

Step1: Write the chemical formula

Lead (II) nitrate is \(Pb(NO_3)_2\), calcium bromide is \(CaBr_2\). The reaction is a double - displacement reaction. The products are lead (II) bromide (\(PbBr_2\), which is insoluble) and calcium nitrate (\(Ca(NO_3)_2\)).
The balanced chemical equation:
$$Pb(NO_3)_2(aq)+CaBr_2(aq)=PbBr_2(s)+Ca(NO_3)_2(aq)$$

Step2: Write the complete ionic equation

Break the soluble ionic compounds into ions. \(Pb(NO_3)_2\) dissociates into \(Pb^{2 +}(aq)+2NO_3^{-}(aq)\), \(CaBr_2\) dissociates into \(Ca^{2+}(aq)+2Br^{-}(aq)\), and \(Ca(NO_3)_2\) dissociates into \(Ca^{2+}(aq)+2NO_3^{-}(aq)\). The complete ionic equation is:
$$Pb^{2 +}(aq)+2NO_3^{-}(aq)+Ca^{2+}(aq)+2Br^{-}(aq)=PbBr_2(s)+Ca^{2+}(aq)+2NO_3^{-}(aq)$$

Step3: Write the net ionic equation

Cancel out the spectator ions (\(Ca^{2+}\) and \(NO_3^{-}\)). The net ionic equation is:
$$Pb^{2 +}(aq)+2Br^{-}(aq)=PbBr_2(s)$$

Answer:

Balanced chemical equation: \(Pb(NO_3)_2(aq)+CaBr_2(aq)=PbBr_2(s)+Ca(NO_3)_2(aq)\)
Complete ionic equation: \(Pb^{2 +}(aq)+2NO_3^{-}(aq)+Ca^{2+}(aq)+2Br^{-}(aq)=PbBr_2(s)+Ca^{2+}(aq)+2NO_3^{-}(aq)\)
Net ionic equation: \(Pb^{2 +}(aq)+2Br^{-}(aq)=PbBr_2(s)\)