Question

yes.
no, it has the wrong number of valence electrons.
the correct number is:
no, it has the right number of valence electrons but doesnt satisfy the octet rule.
the symbols of the problem atoms are: *

• if two or more atoms of the same element dont satisfy the octet rule, just enter the chemical symbol as many times as necessary. for example, if two oxygen atoms dont satisfy the octet rule, enter \o,o\.

Explanation:

Step1: Calculate the number of valence electrons

Hydrogen (\(H\)) has \(1\) valence electron, and oxygen (\(O\)) has \(6\) valence electrons. The ion \([H - H - O - H]^+\) has \(3\) \(H\) atoms and \(1\) \(O\) atom. The total number of valence electrons without considering the charge is \(3\times1 + 6=9\). Since it is a \(+ 1\) ion (loses one electron), the number of valence electrons should be \(9 - 1=8\).

Step2: Check the octet rule

For the octet rule, atoms (except \(H\)) should have \(8\) electrons in their valence shell. \(H\) follows the duet rule ( \(2\) electrons). In the given structure, the central \(O\) atom has \(2\) single bonds ( \(2\) pairs of electrons from bonds) and \(2\) lone pairs ( \(2\) pairs of non - bonding electrons). The total number of electrons around \(O\) is \(2\times2+2\times2 = 8\). But the second \(H\) atom (the one between two \(H\) atoms) has \(2\) bonds ( \(4\) electrons), which violates the duet rule.

Answer:

No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are: \(H\)