ws 2: ionic bonding with transition metals and polyatomic ions
make sure you use the criss cross method correctly, and use the naming rules to name correctly.
- metal names stay the same
- nonmetals must get the suffix of -ide
- transition metals (groups 3 - 12) must have roman numerals in their name
- chromium (ii)→(ii) tells you that this chromium has a +2 charge
- you can figure out the charge of the transition metal by completing the criss cross method backwards. the subscript on the nonmetal would become the charge for the transition metals
- polyatomic ions are units, and should not be separated.
- use your reference sheet to figure out the name or formula for the polyatomic ion.
- if there are multiples of the polyatomic ion, put the polyatomic ion in parentheses
to complete the table below:
- you will break into your lab groups.
- at each station are 4 cards with names on them and numbers. those numbers correspond to the question name on the table below.
- complete the compound using the cards at the stations. determine the formula and compound name for each.

| metal or transition metal | nonmetal or polyatomic ion | formula | compound name |
| ---- | ---- | ---- | ---- |
| 1. sodium | | | |
| 2. calcium | | | |
| 3. copper (ii) | | | |
| 4. lead (iv) | | | |
| | 5. nitride | | |
| | 6. borate | | |
| | 7. iodide | | |
| | 8. sulfite | | |

Question

ws 2: ionic bonding with transition metals and polyatomic ions
make sure you use the criss cross method correctly, and use the naming rules to name correctly.
- metal names stay the same
- nonmetals must get the suffix of -ide
- transition metals (groups 3 - 12) must have roman numerals in their name
  - chromium (ii)→(ii) tells you that this chromium has a +2 charge
  - you can figure out the charge of the transition metal by completing the criss cross method backwards. the subscript on the nonmetal would become the charge for the transition metals
- polyatomic ions are units, and should not be separated.
  - use your reference sheet to figure out the name or formula for the polyatomic ion.
  - if there are multiples of the polyatomic ion, put the polyatomic ion in parentheses
to complete the table below:
- you will break into your lab groups.
- at each station are 4 cards with names on them and numbers. those numbers correspond to the question name on the table below.
- complete the compound using the cards at the stations. determine the formula and compound name for each.

| metal or transition metal | nonmetal or polyatomic ion | formula | compound name |
| ---- | ---- | ---- | ---- |
| 1. sodium |  |  |  |
| 2. calcium |  |  |  |
| 3. copper (ii) |  |  |  |
| 4. lead (iv) |  |  |  |
|  | 5. nitride |  |  |
|  | 6. borate |  |  |
|  | 7. iodide |  |  |
|  | 8. sulfite |  |  |

Accepted Answer

# Explanation:
## Step1: Recall ion - charge of sodium
Sodium (Na) has a + 1 charge ($Na^{+}$).
## Step2: Assume non - metal or polyatomic ion with charge
Let's assume a non - metal or polyatomic ion. For simplicity, if we consider chloride ($Cl^{-}$), using the criss - cross method, the formula is $NaCl$ and the name is sodium chloride.
## Step3: Recall ion - charge of calcium
Calcium (Ca) has a + 2 charge ($Ca^{2 +}$). If we consider chloride ($Cl^{-}$), by criss - cross method, the formula is $CaCl_{2}$ and the name is calcium chloride.
## Step4: Recall ion - charge of copper(II)
Copper(II) has a + 2 charge ($Cu^{2+}$). If we consider chloride ($Cl^{-}$),  by criss - cross method, the formula is $CuCl_{2}$ and the name is copper(II) chloride.
## Step5: Recall ion - charge of lead(IV)
Lead(IV) has a + 4 charge ($Pb^{4+}$). If we consider chloride ($Cl^{-}$), by criss - cross method, the formula is $PbCl_{4}$ and the name is lead(IV) chloride.
## Step6: For nitride ($N^{3 -}$)
With sodium ($Na^{+}$), by criss - cross method, the formula is $Na_{3}N$ and the name is sodium nitride. With calcium ($Ca^{2+}$), the formula is $Ca_{3}N_{2}$ and the name is calcium nitride. With copper(II) ($Cu^{2+}$), the formula is $Cu_{3}N_{2}$ and the name is copper(II) nitride. With lead(IV) ($Pb^{4+}$), the formula is $Pb_{3}N_{4}$ and the name is lead(IV) nitride.
## Step7: For borate (assuming $BO_{3}^{3 -}$)
With sodium ($Na^{+}$), by criss - cross method, the formula is $Na_{3}BO_{3}$ and the name is sodium borate. With calcium ($Ca^{2+}$), the formula is $Ca_{3}(BO_{3})_{2}$ and the name is calcium borate. With copper(II) ($Cu^{2+}$), the formula is $Cu_{3}(BO_{3})_{2}$ and the name is copper(II) borate. With lead(IV) ($Pb^{4+}$), the formula is $Pb_{3}(BO_{3})_{4}$ and the name is lead(IV) borate.
## Step8: For iodide ($I^{-}$)
With sodium ($Na^{+}$), the formula is $NaI$ and the name is sodium iodide. With calcium ($Ca^{2+}$), the formula is $CaI_{2}$ and the name is calcium iodide. With copper(II) ($Cu^{2+}$), the formula is $CuI_{2}$ and the name is copper(II) iodide. With lead(IV) ($Pb^{4+}$), the formula is $PbI_{4}$ and the name is lead(IV) iodide.
## Step9: For sulfite ($SO_{3}^{2 -}$)
With sodium ($Na^{+}$), by criss - cross method, the formula is $Na_{2}SO_{3}$ and the name is sodium sulfite. With calcium ($Ca^{2+}$), the formula is $CaSO_{3}$ and the name is calcium sulfite. With copper(II) ($Cu^{2+}$), the formula is $CuSO_{3}$ and the name is copper(II) sulfite. With lead(IV) ($Pb^{4+}$), the formula is $Pb(SO_{3})_{2}$ and the name is lead(IV) sulfite.

# Answer:
| Metal or Transition Metal | Nonmetal or Polyatomic ion | Formula | Compound Name |
|---|---|---|---|
| Sodium | Chloride | $NaCl$ | Sodium chloride |
| Calcium | Chloride | $CaCl_{2}$ | Calcium chloride |
| Copper(II) | Chloride | $CuCl_{2}$ | Copper(II) chloride |
| Lead(IV) | Chloride | $PbCl_{4}$ | Lead(IV) chloride |
| Sodium | Nitride | $Na_{3}N$ | Sodium nitride |
| Calcium | Nitride | $Ca_{3}N_{2}$ | Calcium nitride |
| Copper(II) | Nitride | $Cu_{3}N_{2}$ | Copper(II) nitride |
| Lead(IV) | Nitride | $Pb_{3}N_{4}$ | Lead(IV) nitride |
| Sodium | Borate | $Na_{3}BO_{3}$ | Sodium borate |
| Calcium | Borate | $Ca_{3}(BO_{3})_{2}$ | Calcium borate |
| Copper(II) | Borate | $Cu_{3}(BO_{3})_{2}$ | Copper(II) borate |
| Lead(IV) | Borate | $Pb_{3}(BO_{3})_{4}$ | Lead(IV) borate |
| Sodium | Iodide | $NaI$ | Sodium iodide |
| Calcium | Iodide | $CaI_{2}$ | Calcium iodide |
| Copper(II) | Iodide | $CuI_{2}$ | Copper(II) iodide |
| Lead(IV) | Iodide | $PbI_{4}$ | Lead(IV) iodide |
| Sodium | Sulfite | $Na_{2}SO_{3}$ | Sodium sulfite |
| Calcium | Sulfite | $CaSO_{3}$ | Calcium sulfite |
| Copper(II) | Sulfite | $CuSO_{3}$ | Copper(II) sulfite |
| Lead(IV) | Sulfite | $Pb(SO_{3})_{2}$ | Lead(IV) sulfite |

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QUESTION IMAGE

Question

Explanation:

Step1: Recall ion - charge of sodium

Step2: Assume non - metal or polyatomic ion with charge

Step3: Recall ion - charge of calcium

Step4: Recall ion - charge of copper(II)

Step5: Recall ion - charge of lead(IV)

Step6: For nitride ($N^{3 -}$)

Step7: For borate (assuming $BO_{3}^{3 -}$)

Step8: For iodide ($I^{-}$)

Step9: For sulfite ($SO_{3}^{2 -}$)

Answer:

metal or transition metal	nonmetal or polyatomic ion	formula	compound name
2. calcium
3. copper (ii)
4. lead (iv)
	5. nitride
	6. borate
	7. iodide
	8. sulfite

Metal or Transition Metal	Nonmetal or Polyatomic ion	Formula	Compound Name
Calcium	Chloride	$CaCl_{2}$	Calcium chloride
Copper(II)	Chloride	$CuCl_{2}$	Copper(II) chloride
Lead(IV)	Chloride	$PbCl_{4}$	Lead(IV) chloride
Sodium	Nitride	$Na_{3}N$	Sodium nitride
Calcium	Nitride	$Ca_{3}N_{2}$	Calcium nitride
Copper(II)	Nitride	$Cu_{3}N_{2}$	Copper(II) nitride
Lead(IV)	Nitride	$Pb_{3}N_{4}$	Lead(IV) nitride
Sodium	Borate	$Na_{3}BO_{3}$	Sodium borate
Calcium	Borate	$Ca_{3}(BO_{3})_{2}$	Calcium borate
Copper(II)	Borate	$Cu_{3}(BO_{3})_{2}$	Copper(II) borate
Lead(IV)	Borate	$Pb_{3}(BO_{3})_{4}$	Lead(IV) borate
Sodium	Iodide	$NaI$	Sodium iodide
Calcium	Iodide	$CaI_{2}$	Calcium iodide
Copper(II)	Iodide	$CuI_{2}$	Copper(II) iodide
Lead(IV)	Iodide	$PbI_{4}$	Lead(IV) iodide
Sodium	Sulfite	$Na_{2}SO_{3}$	Sodium sulfite
Calcium	Sulfite	$CaSO_{3}$	Calcium sulfite
Copper(II)	Sulfite	$CuSO_{3}$	Copper(II) sulfite
Lead(IV)	Sulfite	$Pb(SO_{3})_{2}$	Lead(IV) sulfite