Question

write full electron configurations for b. express your answer in complete form in order of increasing orbital energy as a string without blank space between orbitals. for example, (1 s^{2} 2 s^{2}) should be entered as (1 s^{wedge} 22 s^{wedge} 2). part f complete previous part(s) part g write full electron configurations for k. express your answer in complete form in order of increasing orbital energy as a string without blank space between orbitals. for example, (1 s^{2} 2 s^{2}) should be entered as (1 s^{wedge} 22 s^{wedge} 2).

Explanation:

Step1: Determine the atomic number of B

B is boron, and its atomic number is 5.

Step2: Fill electrons according to the Aufbau principle

Electrons fill orbitals in the order of increasing energy: \(1s<2s<2p\).
For B (\(Z = 5\)):

• \(1s\) orbital can hold 2 electrons: \(1s^{2}\)
• \(2s\) orbital can hold 2 electrons: \(2s^{2}\)
• Remaining \(5-(2 + 2)=1\) electron goes to \(2p\) orbital: \(2p^{1}\)

Step3: Write the electron configuration as a string

Combining the orbitals without spaces: \(1s^{\wedge}22s^{\wedge}22p^{\wedge}1\)

Step4: Determine the atomic number of K

K is potassium, and its atomic number is 19.

Step5: Fill electrons according to the Aufbau principle

Electrons fill orbitals in the order \(1s<2s<2p<3s<3p<4s\)

• \(1s^{2}\)
• \(2s^{2}\)
• \(2p^{6}\)
• \(3s^{2}\)
• \(3p^{6}\)
• Remaining \(19-(2 + 2+6 + 2+6)=1\) electron goes to \(4s\) orbital: \(4s^{1}\)

Step6: Write the electron configuration as a string

Combining the orbitals without spaces: \(1s^{\wedge}22s^{\wedge}22p^{\wedge}63s^{\wedge}23p^{\wedge}64s^{\wedge}1\)

Answer:

For B: \(1s^{\wedge}22s^{\wedge}22p^{\wedge}1\)
For K: \(1s^{\wedge}22s^{\wedge}22p^{\wedge}63s^{\wedge}23p^{\wedge}64s^{\wedge}1\)