Question

write the concentration equilibrium constant expression for this reaction.

cu²⁺(aq)+2ag(s)→cu(s)+2ag⁺(aq)

Explanation:

Step1: Recall the formula for equilibrium constant

For a reaction \(aA + bB
ightleftharpoons cC + dD\), the equilibrium constant \(K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}\), where \([X]\) is the concentration of species \(X\), and \(a,b,c,d\) are stoichiometric coefficients. Solids (\(Ag(s)\) and \(Cu(s)\)) have constant activity (concentration is considered as \(1\) in the equilibrium - constant expression).

Step2: Apply the formula to the given reaction

For the reaction \(Cu^{2 +}(aq)+2Ag(s)
ightleftharpoons Cu(s)+2Ag^{+}(aq)\), using the formula \(K_c=\frac{[products]}{[reactants]}\) (with appropriate exponents from stoichiometry and ignoring solids). The concentration of \(Cu(s)\) and \(Ag(s)\) is \(1\). So, \(K_c=\frac{[Ag^{+}]^{2}}{[Cu^{2 +}]}\)

Answer:

\(K_c=\frac{[Ag^{+}]^{2}}{[Cu^{2 +}]}\)