1.
which reaction between halogens and halide salts
will occur?
a. $\ce{f_{2}(g) + fei_{2}(aq) - fef_{2}(aq) + i_{2}(l)}$
b. $\ce{i_{2}(g) + mnbr_{2}(aq) - mni_{2}(aq) + br_{2}(g)}$
c. $\ce{cl_{2}(g) + srf_{2}(aq) - srcl_{2}(aq) + f_{2}(g)}$
d. $\ce{br_{2}(l) + cocl_{2}(aq) - cobr_{2}(aq) + cl_{2}(g)}$
2. over 99% of the mass of an atom is located
a. in the nucleus c. in the neutrons
b. in the protons d. in the electron cloud
3.
finely ground nickel(ii) hydroxide is placed in
a beaker of water. it sinks to the bottom of the beaker
and remains unchanged. an aqueous solution of
hydrochloric acid (hcl) is then added to the beaker,
and the $\ce{ni(oh)_{2}}$ disappears. which equation best
describes what occurred in the beaker?
a. $\ce{ni(oh)_{2}(s) + hcl(aq) - \underset{}{nio(aq) + h_{2}(g) + hcl(aq)}}$
b. $\ce{ni(oh)_{2}(s) + 2hcl(aq) - nicl_{2}(aq) + 2h_{2}o(l)}$
c. $\ce{ni(oh)_{2}(s) + 2h_{2}o(l) - nicl_{2}(aq) + 2h_{2}o(l)}$
d. $\ce{ni(oh)_{2}(s) + 2h_{2}o(l) - \underset{}{nicl_{2}(aq) + 3h_{2}o(l) + o_{2}(g)}}$
4. using the rules we learned in class, name this compound: $\ce{cof_{3}}$.
a. cobalt fluoride. c. cobalt(ii) fluoride
b. cobalt trifluoride d. cobalt(iii) fluoride
5. using the rules we learned in class, name this compound: $\ce{ca(oh)_{2}}$.
a. calcium hydroxide c. calcium(ii) hydroxide
b. calcium oxide hydrate d. calcium(ii) oxide hydride
6. which two elements are most likely to form a compound?
a. mg and s c. mg and ar
b. na and ar d. na and mg
7. which of these represents the correct electron configuration for carbon?
a. $1s^{2}2s^{2}2p^{2}$ c. $1s^{2}2p^{2}2s^{2}$
b. $1s^{2}2s^{2}2p^{6}3s^{2}$ d. $1s^{2}2s^{4}$

Question

1.
which reaction between halogens and halide salts
will occur?
a. $\ce{f_{2}(g) + fei_{2}(aq) -> fef_{2}(aq) + i_{2}(l)}$
b. $\ce{i_{2}(g) + mnbr_{2}(aq) -> mni_{2}(aq) + br_{2}(g)}$
c. $\ce{cl_{2}(g) + srf_{2}(aq) -> srcl_{2}(aq) + f_{2}(g)}$
d. $\ce{br_{2}(l) + cocl_{2}(aq) -> cobr_{2}(aq) + cl_{2}(g)}$
2. over 99% of the mass of an atom is located
   a. in the nucleus 				c. in the neutrons
   b. in the protons 				d. in the electron cloud
3.
finely ground nickel(ii) hydroxide is placed in
a beaker of water. it sinks to the bottom of the beaker
and remains unchanged. an aqueous solution of
hydrochloric acid (hcl) is then added to the beaker,
and the $\ce{ni(oh)_{2}}$ disappears. which equation best
describes what occurred in the beaker?
a. $\ce{ni(oh)_{2}(s) + hcl(aq) -> \underset{}{nio(aq) + h_{2}(g) + hcl(aq)}}$
b. $\ce{ni(oh)_{2}(s) + 2hcl(aq) -> nicl_{2}(aq) + 2h_{2}o(l)}$
c. $\ce{ni(oh)_{2}(s) + 2h_{2}o(l) -> nicl_{2}(aq) + 2h_{2}o(l)}$
d. $\ce{ni(oh)_{2}(s) + 2h_{2}o(l) -> \underset{}{nicl_{2}(aq) + 3h_{2}o(l) + o_{2}(g)}}$
4. using the rules we learned in class, name this compound: $\ce{cof_{3}}$.
   a. cobalt fluoride. 				c. cobalt(ii) fluoride
   b. cobalt trifluoride 			d. cobalt(iii) fluoride
5. using the rules we learned in class, name this compound: $\ce{ca(oh)_{2}}$.
   a. calcium hydroxide 			c. calcium(ii) hydroxide
   b. calcium oxide hydrate 		d. calcium(ii) oxide hydride
6. which two elements are most likely to form a compound?
   a. mg and s 					c. mg and ar
   b. na and ar 					d. na and mg
7. which of these represents the correct electron configuration for carbon?
   a. $1s^{2}2s^{2}2p^{2}$ 				c. $1s^{2}2p^{2}2s^{2}$
   b. $1s^{2}2s^{2}2p^{6}3s^{2}$ 		d. $1s^{2}2s^{4}$

Accepted Answer

### Question 1
# Explanation:
## Step1: Recall Halogen Reactivity
Halogens (F, Cl, Br, I) have decreasing reactivity: $ F_2 > Cl_2 > Br_2 > I_2 $. A halogen can displace a less reactive halide from its salt.
## Step2: Analyze Option A
$ F_2(g) + FeI_2(aq)
ightarrow FeF_2(aq) + I_2(l) $: $ F_2 $ (more reactive) displaces $ I^- $ (from $ FeI_2 $)—valid.
## Step3: Analyze Option B
$ I_2(g) + MnBr_2(aq)
ightarrow MnI_2(aq) + Br_2(g) $: $ I_2 $ (less reactive than $ Br_2 $) can’t displace $ Br^- $—invalid.
## Step4: Analyze Option C
$ Cl_2(g) + SrF_2(aq)
ightarrow SrCl_2(aq) + F_2(g) $: $ Cl_2 $ (less reactive than $ F_2 $) can’t displace $ F^- $—invalid.
## Step5: Analyze Option D
$ Br_2(l) + CoCl_2(aq)
ightarrow CoBr_2(aq) + Cl_2(g) $: $ Br_2 $ (less reactive than $ Cl_2 $) can’t displace $ Cl^- $—invalid.
# Answer: A. $ \boldsymbol{F_2(g) + FeI_2(aq)
ightarrow FeF_2(aq) + I_2(l)} $

### Question 2
# Brief Explanations:
An atom’s mass is mostly in the nucleus (contains protons + neutrons; electrons have negligible mass). Protons/neutrons alone don’t account for “over 99%” (nucleus as a whole does). Electron cloud has negligible mass.
# Answer: a. In the nucleus

### Question 3
# Explanation:
## Step1: Identify Reaction Type
$ Ni(OH)_2(s) $ (base) reacts with $ HCl(aq) $ (acid) in a neutralization reaction: acid + base → salt + water.
## Step2: Analyze Option A
$ Ni(OH)_2(s) + HCl(aq)
ightarrow NiO(aq) + H_2(g) + HCl(aq) $: Incorrect products (no $ H_2 $, $ NiO $ not formed).
## Step3: Analyze Option B
$ Ni(OH)_2(s) + 2HCl(aq)
ightarrow NiCl_2(aq) + 2H_2O(l) $: Acid (HCl) + base ($ Ni(OH)_2 $) → salt ($ NiCl_2 $) + water ($ H_2O $)—valid.
## Step4: Analyze Option C
$ Ni(OH)_2(s) + 2H_2O(l)
ightarrow NiCl_2(aq) + 2H_2O(l) $: No HCl reactant, invalid.
## Step5: Analyze Option D
$ Ni(OH)_2(s) + 2H_2O(l)
ightarrow NiCl_2(aq) + 3H_2O(l) + O_2(g) $: Incorrect products (no $ O_2 $, wrong reactants).
# Answer: B. $ \boldsymbol{Ni(OH)_2(s) + 2HCl(aq)
ightarrow NiCl_2(aq) + 2H_2O(l)} $

### Question 4
# Explanation:
## Step1: Determine Cobalt’s Charge
In $ CoF_3 $, $ F $ has $ -1 $ charge. Let $ Co $ charge be $ x $: $ x + 3(-1) = 0 $ → $ x = +3 $.
## Step2: Name the Compound
For transition metals with variable charges, use Roman numerals. $ Co^{3+} $ is cobalt(III), $ F^- $ is fluoride. So “Cobalt(III) fluoride”.
## Step3: Eliminate Options
- a: No charge (Co can be +2/+3) → wrong.
- b: “Trifluoride” is for covalent, $ CoF_3 $ is ionic → wrong.
- c: $ Co^{2+} $ would be cobalt(II), but here $ Co $ is +3 → wrong.
# Answer: d. Cobalt(III) fluoride

### Question 5
# Explanation:
## Step1: Identify Ions
$ Ca(OH)_2 $ has $ Ca^{2+} $ (calcium) and $ OH^- $ (hydroxide).
## Step2: Name the Compound
Ionic compound: cation (calcium) + anion (hydroxide). Calcium has fixed charge (+2), so no Roman numeral needed. Name: Calcium hydroxide.
## Step3: Eliminate Options
- b: “Oxide hydrate” is incorrect (no oxide/hydrate here).
- c: $ Ca^{2+} $ is fixed, no (II) needed.
- d: Incorrect ions (no oxide/hydride).
# Answer: a. Calcium hydroxide

### Question 6
# Explanation:
## Step1: Recall Bonding Tendency
Elements form compounds to achieve octet. Metals (Mg, Na) react with nonmetals (S); noble gases (Ar) are inert (unlikely to react).
## Step2: Analyze Option A
Mg (metal) + S (nonmetal): Form ionic compound (e.g., $ MgS $) → likely.
## Step3: Analyze Option B
Na (metal) + Ar (noble gas): Ar is inert → no reaction.
## Step4: Analyze Option C
Mg (metal) + Ar (noble gas): Ar is inert → no reaction.
## Step5: Analyze Option D
Na (metal) + Mg (metal): Both metals, unlikely to form compound (form alloys, not compounds).
# Answer: a. Mg and S

### Question 7
# Explanation:
## Step1: Carbon’s Atomic Number
Carbon (C) has atomic number 6, so 6 electrons.
## Step2: Electron Configuration Rules
Fill orbitals: $ 1s^2 $ (2e⁻), $ 2s^2 $ (2e⁻), then $ 2p^2 $ (remaining 2e⁻). So $ 1s^2 2s^2 2p^2 $.
## Step3: Eliminate Options
- b: Too many electrons (10, for Ne) → wrong.
- c: $ 2p^2 $ comes after $ 2s^2 $, order wrong.
- d: Only 5 electrons → wrong.
# Answer: a. $ \boldsymbol{1s^2 2s^2 2p^2} $

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Question 1

Step1: Recall Halogen Reactivity

Step2: Analyze Option A

Step3: Analyze Option B

Step4: Analyze Option C

Step5: Analyze Option D

Step1: Identify Reaction Type

Step2: Analyze Option A

Step3: Analyze Option B

Step4: Analyze Option C

Step5: Analyze Option D

Answer:

Question 2