Question

which element below has the highest electronegativity?
p
be
b
n
c

Explanation:

Electronegativity increases across a period from left to right in the periodic table. Among the given elements, \(Be\), \(B\), \(C\), \(N\) are in the same period (period 2). \(P\) is in period 3. In period 2, the order of electronegativity from left to right is \(Be < B < C < N\). Since \(P\) is in a lower - period compared to \(N\) (and considering the general trend of electronegativity across periods and groups, with the main trend being higher electronegativity towards the right in a period), \(N\) has a higher electronegativity than \(P\).

Answer:

N