when $\text{mgcl}_2$ reacts with $\text{na}_3\text{po}_4$, $\text{nacl}$ and $\text{mg}_3(\text{po}_4)_2$ are produced as shown in the following balanced chemical equation.

\3\text{mgcl}_2 + 2\text{na}_3\text{po}_4 \longrightarrow 6\text{nacl} + \text{mg}_3(\text{po}_4)_2\

suppose $19.03\text{ g mgcl}_2$ reacts with $20.71\text{ g na}_3\text{po}_4$.

determine how many moles of $\text{mg}_3(\text{po}_4)_2$ will be produced if $19.03\text{ g mgcl}_2$ reacts with excess $\text{na}_3\text{po}_4$. the molar mass of $\text{mgcl}_2$ is $95.211\text{ g/mol}$.

$\text{mg}_3(\text{po}_4)_2$: mol

determine how many moles of $\text{mg}_3(\text{po}_4)_2$ will be produced if $20.71\text{ g na}_3\text{po}_4$ reacts with excess $\text{mgcl}_2$. the molar mass of $\text{na}_3\text{po}_4$ is $163.94\text{ g/mol}$.

$\text{mg}_3(\text{po}_4)_2$: mol

what is the limiting reactant?
( ) $\text{na}_3\text{po}_4$
( ) $\text{mgcl}_2$

Question

when $\text{mgcl}_2$ reacts with $\text{na}_3\text{po}_4$, $\text{nacl}$ and $\text{mg}_3(\text{po}_4)_2$ are produced as shown in the following balanced chemical equation.

\3\text{mgcl}_2 + 2\text{na}_3\text{po}_4 \longrightarrow 6\text{nacl} + \text{mg}_3(\text{po}_4)_2\

suppose $19.03\text{ g mgcl}_2$ reacts with $20.71\text{ g na}_3\text{po}_4$.

determine how many moles of $\text{mg}_3(\text{po}_4)_2$ will be produced if $19.03\text{ g mgcl}_2$ reacts with excess $\text{na}_3\text{po}_4$. the molar mass of $\text{mgcl}_2$ is $95.211\text{ g/mol}$.

$\text{mg}_3(\text{po}_4)_2$:   mol

determine how many moles of $\text{mg}_3(\text{po}_4)_2$ will be produced if $20.71\text{ g na}_3\text{po}_4$ reacts with excess $\text{mgcl}_2$. the molar mass of $\text{na}_3\text{po}_4$ is $163.94\text{ g/mol}$.

$\text{mg}_3(\text{po}_4)_2$:   mol

what is the limiting reactant?
( ) $\text{na}_3\text{po}_4$
( ) $\text{mgcl}_2$

Accepted Answer

{ "quality": "clear", "question_count": 3, "skills_matched": [ "step_cot", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Stoichiometry", "Limiting Reactant" ], "new_concepts": [], "current_concepts": [ "Stoichiometry", "Limiting Reactant" ] } ## Calculate moles of product from magnesium chloride Using the *Stoichiometry* knowledge point $$ \begin{aligned} n(\text{MgCl}_2) &= \frac{19.03\text{ g}}{95.211\text{ g/mol}} \approx 0.19987\text{ mol}\ n(\text{Mg}_3(\text{PO}_4)_2) &= 0.19987\text{ mol MgCl}_2 \times \frac{1\text{ mol Mg}_3(\text{PO}_4)_2}{3\text{ mol MgCl}_2} \approx 0.06662\text{ mol} \end{aligned} $$ ## Calculate moles of product from sodium phosphate Using the *Stoichiometry* knowledge point $$ \begin{aligned} n(\text{Na}_3\text{PO}_4) &= \frac{20.71\text{ g}}{163.94\text{ g/mol}} \approx 0.12633\text{ mol}\ n(\text{Mg}_3(\text{PO}_4)_2) &= 0.12633\text{ mol Na}_3\text{PO}_4 \times \frac{1\text{ mol Mg}_3(\text{PO}_4)_2}{2\text{ mol Na}_3\text{PO}_4} \approx 0.06317\text{ mol} \end{aligned} $$ ## Determine the limiting reactant Using the *Limiting Reactant* knowledge point $$ \begin{aligned} 0.06317\text{ mol} &< 0.06662\text{ mol}\ \text{Limiting Reactant} &= \text{Na}_3\text{PO}_4 \end{aligned} $$ ## Question 1 $0.06662$ ## Question 2 $0.06317$ ## Question 3 $\text{Na}_3\text{PO}_4$

$\text{MgCl}_2$

{ "subject": "Natural Science", "question_type": "Multi-part", "knowledge_point": [ "Natural Science", "Chemistry", "Stoichiometry" ] }

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QUESTION IMAGE

Question

Explanation:

Calculate moles of product from magnesium chloride

Calculate moles of product from sodium phosphate

Determine the limiting reactant

Answer:

Question 1

Question 2

Question 3