Question

1. when ( ^{211}_{84}\text{po} ) emits a beta particle, it transforms into a new element.

a. write out the nuclear equation:

b. fill out the chart below:

	parent element	daughter element
atomic number
atomic mass
# of protons
# of electrons
# of neutrons

Explanation:

Step1: Recall Beta Decay Rules

In beta decay ($\beta^-$), a neutron turns into a proton, so the atomic number ($Z$) increases by 1, mass number ($A$) remains the same. For $\ce{^{211}_{84}Po}$: $A = 211$, $Z = 84$. After beta decay, daughter has $Z = 84 + 1 = 85$ (Atatine, $\ce{At}$), $A = 211$. Beta particle is $\ce{^{0}_{-1}e}$.

Step2: Write Nuclear Equation

The nuclear equation is $\ce{^{211}_{84}Po
ightarrow ^{211}_{85}At + ^{0}_{-1}e}$.

Step3: Fill Parent Element Details

Parent: Polonium ($\ce{Po}$), $Z = 84$, $A = 211$, protons = 84, electrons = 84 (neutral), neutrons = $211 - 84 = 127$.

Step4: Fill Daughter Element Details

Daughter: Astatine ($\ce{At}$), $Z = 85$, $A = 211$, protons = 85, electrons = 85 (neutral), neutrons = $211 - 85 = 126$. Beta particle: $\ce{^{0}_{-1}e}$, protons = 0, electrons = -1 (charge), neutrons = 0.

Answer:

Part a: Nuclear Equation

$\boldsymbol{\ce{^{211}_{84}Po
ightarrow ^{211}_{85}At + ^{0}_{-1}e}}$

Part b: Filled Chart (Rows: Parent, Daughter, Beta Particle)

	Name of Element	Atomic Number	Atomic Mass	# of Protons	# of Electrons	# of Neutrons
Daughter	Astatine (At)	85	211	85	85	126
Beta	Beta Particle	-1	0	0	-1 (charge)	0