Question

what is the volume when 524 cm3 of a gas at 491 k is cooled to 297 k?
v₁ = 524 cm³ t₁ = 491 k
v₂ = ? cm³ t₂ = 297 k
assume the pressure and number of moles are constant.
317 cm³
739 cm³
866 cm³

Explanation:

Step1: Apply Charles's Law

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

Step2: Rearrange for $V_2$

$V_2 = V_1 \times \frac{T_2}{T_1}$

Step3: Substitute values

$V_2 = 524 \, \text{cm}^3 \times \frac{297 \, \text{K}}{491 \, \text{K}}$

Step4: Calculate result

$V_2 \approx 317 \, \text{cm}^3$

Answer:

317 cm³