Question

1. what volume at stp does 88.0 g of co₂ occupy?

options: 44.79l, 22.40l, 11.2l, 56.0 l

Explanation:

Step1: Calculate moles of \( CO_2 \)

Molar mass of \( CO_2 \) is \( 12 + 2\times16 = 44 \, \text{g/mol} \). Moles \( n = \frac{\text{mass}}{\text{molar mass}} = \frac{88.0 \, \text{g}}{44 \, \text{g/mol}} = 2 \, \text{mol} \).

Step2: Use molar volume at STP

At STP, 1 mole of gas occupies \( 22.4 \, \text{L} \). Volume \( V = n \times 22.4 \, \text{L/mol} = 2 \, \text{mol} \times 22.4 \, \text{L/mol} = 44.8 \, \text{L} \)? Wait, no, wait, 222.4 is 44.8? Wait, the options have 44.79L (close to 44.8L). Wait, maybe my step1: 88g /44g/mol = 2mol. Then volume is 2mol 22.4L/mol = 44.8L, which is approximately 44.79L. Wait, but let's check again. Wait, maybe I made a mistake. Wait, 44g/mol, 88g is 2 moles. At STP, molar volume is 22.4L/mol. So 2*22.4 = 44.8L, which is 44.79L (due to more precise molar volume maybe 22.39L/mol). So the correct volume is 44.79L.

Answer:

44.79L