what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by dilution?

$m_1 = 2.5\text{ m}$ $v_1 = ?\text{ ml}$
$m_2 = 1.0\text{ m}$ $v_2 = 150\text{ ml}$

\m_1v_1 = m_2v_2\

? $\text{ml lino}_3$

Question

what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by dilution?

$m_1 = 2.5\text{ m}$ $v_1 = ?\text{ ml}$
$m_2 = 1.0\text{ m}$ $v_2 = 150\text{ ml}$

\m_1v_1 = m_2v_2\

?  $\text{ml lino}_3$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Dilution Equation" ], "new_concepts": [], "current_concepts": [ "Dilution Equation", "Solution Concentration" ] } ## Identify the given variables $$ \begin{aligned} M_1 &= 2.5\text{ M}\ M_2 &= 1.0\text{ M}\ V_2 &= 150\text{ mL} \end{aligned} $$ ## Rearrange the dilution equation for the unknown volume $$ \begin{aligned} M_1 V_1 &= M_2 V_2\ V_1 &= \frac{M_2 V_2}{M_1} \end{aligned} $$ ## Substitute the values and calculate $$ \begin{aligned} V_1 &= \frac{1.0\text{ M} \times 150\text{ mL}}{2.5\text{ M}}\ V_1 &= 60\text{ mL} \end{aligned} $$ What volume of a 2.5 M lithium nitrate solution would be needed to make 150 mL of a 1.0 M solution by dilution? $M_1 = 2.5\text{ M}\quad V_1 = ?\text{ mL}$ $M_2 = 1.0\text{ M}\quad V_2 = 150\text{ mL}$ $M_1 V_1 = M_2 V_2$ 60 $\text{mL LiNO}_3$ { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Chemistry", "Dilution Equation" ] }

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QUESTION IMAGE

Question

Explanation:

Identify the given variables

Rearrange the dilution equation for the unknown volume

Substitute the values and calculate

Answer: