Question

what volume of 18.0 m h₂so₄ is required to prepare 250.0 ml of 0.500 m h₂so₄?

Explanation:

Step1: Write the dilution formula

$$C_1V_1 = C_2V_2$$
where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.

Step2: Substitute the given values

Given \(C_1 = 18.0\space M\), \(C_2=0.500\space M\), \(V_2 = 250.0\space mL\).
We need to find \(V_1\).
From \(C_1V_1 = C_2V_2\), we can solve for \(V_1\) as \(V_1=\frac{C_2V_2}{C_1}\)
Substitute the values: \(V_1=\frac{0.500\space M\times250.0\space mL}{18.0\space M}\)

Step3: Calculate the value of \(V_1\)

\(V_1=\frac{0.500\times250.0}{18.0}\space mL=\frac{125}{18.0}\space mL\approx 6.94\space mL\)

Answer:

\(6.94\space mL\)