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4. what is the total number of moles of hydrogen gas contained in $9.03…

Question

  1. what is the total number of moles of hydrogen gas contained in $9.03 \times 10^{23}$ molecules?

options:

  • 1.50 moles
  • 2.00 moles
  • 6.02 moles
  • 9.03 moles

clear all

Explanation:

Step1: Recall Avogadro's number

Avogadro's number is \( 6.02 \times 10^{23} \) molecules per mole. The formula to find moles (\( n \)) from number of molecules (\( N \)) is \( n=\frac{N}{N_A} \), where \( N_A = 6.02\times 10^{23}\) molecules/mol.

Step2: Substitute values into the formula

Given \( N = 9.03\times 10^{23}\) molecules and \( N_A=6.02\times 10^{23}\) molecules/mol. So \( n=\frac{9.03\times 10^{23}}{6.02\times 10^{23}}\)

Step3: Simplify the expression

The \( 10^{23} \) terms cancel out, and we calculate \( \frac{9.03}{6.02}=1.50 \) moles.

Answer:

1.50 moles (the option with "1.50 moles")