Question

what is the shorthand electron configuration for sulfur atom? he 3s²3p⁴ na 3s²3p³ ar 3p⁴ ne 3s²3p⁴

Explanation:

Step1: Determine the atomic number of sulfur

The atomic number of sulfur (\(S\)) is \(16\).

Step2: Find the noble gas with fewer electrons

Neon (\(Ne\)) has \(10\) electrons.

Step3: Write the remaining electron configuration

\(16 - 10=6\) electrons left. The remaining electrons fill \(3s\) and \(3p\) orbitals: \(3s^{2}3p^{4}\). So the shorthand electron configuration is \([Ne]3s^{2}3p^{4}\).

Answer:

[Ne] \(3s^{2}3p^{4}\)