Question

what quantity of moles of h₂so₄ are required to completely react with 7.20 mol of al according to the balanced chemical reaction 2 al(s) + 3 h₂so₄(aq) → al₂(so₄)₃(aq) + 3 h₂(g)

Explanation:

Step1: Determine mole ratio

From the balanced equation \(2Al(s)+3H_2SO_4(aq)\to Al_2(SO_4)_3(aq)+3H_2(g)\), the mole ratio of \(Al\) to \(H_2SO_4\) is \(2:3\).

Step2: Set up proportion

Let \(x\) be the moles of \(H_2SO_4\). We have \(\frac{2}{3}=\frac{7.20}{x}\).

Step3: Solve for \(x\)

Cross - multiply: \(2x = 3\times7.20\), so \(x=\frac{3\times7.20}{2}\).
Calculate \(x = 10.8\)

Answer:

\(10.8\)