Question

what is the proportion of moles of sodium azide that are used compared to the moles of sodium produced?
a for every 3 moles of sodium azide used, 3 moles of sodium are produced
b for every 1 mol of sodium azide used, 3 moles of sodium are produced
c for every 2 moles of sodium azide used, 2 moles of sodium are produced
d for every 2 moles of sodium azide used, 3 moles of sodium are produced

Explanation:

Step1: Write the balanced chemical equation

The decomposition of sodium azide (\(NaN_3\)) to produce sodium (\(Na\)) and nitrogen gas (\(N_2\)) is \(2NaN_3
ightarrow 2Na + 3N_2\).

Step2: Analyze the mole ratio

From the balanced equation, for every \(2\) moles of \(NaN_3\) used, \(2\) moles of \(Na\) are produced.

Answer:

C. For every 2 moles of sodium azide used, 2 moles of sodium are produced