Question

what pressure (in atm) does 3.54 moles of chlorine gas at 376 k exert on the walls of its 51.2 l container? ? atm

Explanation:

Step1: Recall ideal gas law

$PV = nRT$ where $R = 0.0821 \frac{\text{L·atm}}{\text{mol·K}}$

Step2: Rearrange for pressure

$P = \frac{nRT}{V}$

Step3: Substitute values

$P = \frac{3.54 \times 0.0821 \times 376}{51.2}$

Step4: Calculate result

$P \approx \frac{3.54 \times 0.0821 \times 376}{51.2} \approx 2.17$

Answer:

2.17