Question

what is the percent mass of 4 g of c₁₂h₂₂o₁₁ in 350 ml of water?
select the correct answer below:
○ 2.63%
○ 5.77%
○ 1.13%
○ 3.49%

Explanation:

Step1: Calculate the mass of water

The density of water is \(1\ g/mL\). Given \(V = 350\ mL\), using the formula \(m=
ho V\), we have \(m_{water}=1\ g/mL\times350\ mL = 350\ g\).

Step2: Calculate the total mass of the solution

The mass of solute \(m_{solute}=4\ g\). The total mass of the solution \(m_{solution}=m_{solute}+m_{water}\). So \(m_{solution}=4\ g + 350\ g=354\ g\).

Step3: Calculate the mass - percent

The formula for mass - percent is \(\text{Mass}\%=\frac{m_{solute}}{m_{solution}}\times100\%\). Substitute \(m_{solute} = 4\ g\) and \(m_{solution}=354\ g\) into the formula: \(\text{Mass}\%=\frac{4}{354}\times 100\%=\frac{400}{354}\%\approx1.13\%\)

Answer:

\(1.13\%\) (the third option)