Question

what is the minimum number of moles of hno₃ needed to produce 8 moles of n₂o₅? 8 16 2 4 12

Explanation:

Step1: Write the balanced chemical equation

The decomposition reaction of \(HNO_3\) to produce \(N_2O_5\) is \(2HNO_3
ightarrow N_2O_5 + H_2O\).

Step2: Use mole - ratio from the balanced equation

From the balanced equation \(2HNO_3
ightarrow N_2O_5 + H_2O\), the mole ratio of \(HNO_3\) to \(N_2O_5\) is \(n(HNO_3):n(N_2O_5)=2:1\).
Let \(n(HNO_3)\) be the number of moles of \(HNO_3\) and \(n(N_2O_5) = 8\) moles.
Using the ratio \(\frac{n(HNO_3)}{n(N_2O_5)}=\frac{2}{1}\), we can solve for \(n(HNO_3)\).
\(n(HNO_3)=2\times n(N_2O_5)\)
Substitute \(n(N_2O_5) = 8\) moles into the equation: \(n(HNO_3)=2\times8=16\) moles.

Answer:

B. 16