Question

1. what mass of sulfur would have precisely 4.7×10²² atoms of sulfur?

2.50 g sulfur
6.02 g sulfur
1.3 g sulfur
4.7 g sulfur
clear all

Explanation:

Step1: Calculate the number of moles of sulfur

Use Avogadro's number \(N_A = 6.02\times10^{23}\text{ atoms/mol}\). The number of moles \(n\) of sulfur is given by \(n=\frac{N}{N_A}\), where \(N = 4.7\times 10^{22}\text{ atoms}\).

$$n=\frac{4.7\times 10^{22}}{6.02\times 10^{23}}=\frac{4.7}{60.2}\text{ mol}\approx0.078\text{ mol}$$

Step2: Calculate the mass of sulfur

The molar mass of sulfur \(M = 32\text{ g/mol}\). Use the formula \(m=n\times M\).

$$m = 0.078\times32\text{ g}\approx2.5\text{ g}$$

Answer:

2.50 g sulfur