Question

what is the formula mass of calcium sulfate dihydrate caso₄·2h₂o? be sure to add the water hydration, which is the 2h₂o part (water surrounding the calcium sulfate).
136 g/mol
164 g/mol
172 g/mol
154 g/mol
question 6
1 pts
in a spacecraft, this reaction occurs:
co₂ (g) + 2lioh (s) → lico₃ (s) + h₂o (l)
how many liters of carbon dioxide will 3 moles of lithium hydroxide (lioh) absorb? (one mole of any gas occupies 22.4 l under certain conditions of temperature and pressure. assume those conditions for this question.)
3.0 l
6.0 l
34 l
20 l

Explanation:

Step1: Determine the mole ratio of \(CO_2\) to \(LiOH\)

From the balanced chemical equation \(CO_2(g)+2LiOH(s)\to Li_2CO_3(s)+H_2O(l)\), the mole ratio of \(CO_2\) to \(LiOH\) is \(1:2\).

Step2: Calculate the moles of \(CO_2\)

Given \(n_{LiOH} = 3\space mol\). Using the mole ratio \(\frac{n_{CO_2}}{n_{LiOH}}=\frac{1}{2}\), we can solve for \(n_{CO_2}\). So \(n_{CO_2}=\frac{1}{2}\times n_{LiOH}=\frac{1}{2}\times3\space mol = 1.5\space mol\)

Step3: Calculate the volume of \(CO_2\)

We know that for a gas, \(V=n\times V_m\), where \(V_m = 22.4\space L/mol\) (molar volume). Substituting \(n = 1.5\space mol\) and \(V_m=22.4\space L/mol\) into the formula, we get \(V=1.5\space mol\times22.4\space L/mol\)

$$V = 33.6\space L\approx34\space L$$

Answer:

34 L