Question

what else is produced during the combustion of butane, c₄h₁₀? 2c₄h₁₀ + 13o₂ → 8_______ + 10h₂o h₂o c₄h₁₀ co₂ o₂

Explanation:

Step1: Analyze the elements in reactants

The reactants are \(2C_{4}H_{10}\) (contains C and H) and \(13O_{2}\) (contains O).

Step2: Analyze the elements in products

The products are \(10H_{2}O\) (contains H and O). We need to find the other product.

Step3: Balance the carbon atoms

In \(2C_{4}H_{10}\), there are \(2\times4 = 8\) carbon atoms. In the product side, if the unknown product is \(CO_{2}\), and there are 8 units of it (\(8CO_{2}\)), then the number of carbon atoms is balanced (\(8\times1=8\)). Also, for oxygen atoms: in reactants \(13O_{2}\) has \(13\times2 = 26\) O atoms. In products, \(10H_{2}O\) has \(10\times1 = 10\) O atoms and \(8CO_{2}\) has \(8\times2=16\) O atoms. \(10 + 16=26\). Hydrogen atoms: in \(2C_{4}H_{10}\) there are \(2\times10 = 20\) H atoms, and in \(10H_{2}O\) there are \(10\times2 = 20\) H atoms.

Answer:

C. \(CO_{2}\)