Question

vitamin c has the formula c h o. you burn 0.0400 g of the compound in a combustion analysis chamber and isolate 0.0600 g of co₂ and 0.0163 g of h₂o. what is the amount of co₂ produced in the analysis, in moles? mol

Explanation:

Step1: Calculate the molar mass of \(CO_2\)

The molar mass of \(CO_2\) is \(M = 12 + 2\times16 = 44\space g/mol\)

Step2: Use the formula \(n=\frac{m}{M}\)

Given \(m = 0.0600\space g\) and \(M = 44\space g/mol\), then \(n=\frac{0.0600}{44}\)

$$n=\frac{0.0600}{44}= 0.00136\space mol$$

Answer:

\(0.00136\space mol\)