Question

the value of the solubility product constant for silver bromide is
write the reaction that corresponds to this ksp value.
ksp values are found by clicking on the \tables\ link.
be sure to specify the state of each reactant or product.
if a box is not needed leave it blank.

Explanation:

Step1: Identify the compound and its dissolution

Silver bromide (AgBr) is a sparingly soluble salt. When it dissolves in water, it dissociates into silver ions (\(Ag^+\)) and bromide ions (\(Br^-\)).

Step2: Write the dissolution reaction

The reaction for the dissolution of silver bromide is \(AgBr(s)
ightleftharpoons Ag^+(aq) + Br^-(aq)\). This reaction represents the equilibrium between the solid silver bromide and its dissolved ions, and the solubility product constant (\(K_{sp}\)) is associated with this equilibrium reaction.

Answer:

\(AgBr(s)
ightleftharpoons Ag^+(aq) + Br^-(aq)\)