Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

use the references to access important values if needed for compare the…

Question

use the references to access important values if needed for
compare the solubility of zinc carbonate in each of the following aqueous solutions:

0.10 m zn(no₃)₂
0.10 m k₂co₃
0.10 m kno₃
0.10 m nh₄ch₃coo

more soluble than in
pure water.
similar solubility as in
pure water.
less soluble than in
pure water.
clear all

Explanation:

To solve this, we analyze the solubility of \( \text{ZnCO}_3 \) using the common ion effect and salt hydrolysis:

Step 1: Analyze \( 0.10 \, \text{M} \, \text{Zn(NO}_3\text{)}_2 \)

\( \text{Zn(NO}_3\text{)}_2 \) dissociates into \( \text{Zn}^{2+} \) and \( \text{NO}_3^- \). \( \text{ZnCO}_3 \) dissociates as \( \text{ZnCO}_3(s)
ightleftharpoons \text{Zn}^{2+}(aq) + \text{CO}_3^{2-}(aq) \). The common ion \( \text{Zn}^{2+} \) from \( \text{Zn(NO}_3\text{)}_2 \) shifts the equilibrium left, decreasing solubility. So, less soluble than pure water.

Step 2: Analyze \( 0.10 \, \text{M} \, \text{K}_2\text{CO}_3 \)

\( \text{K}_2\text{CO}_3 \) dissociates into \( \text{K}^+ \) and \( \text{CO}_3^{2-} \). The common ion \( \text{CO}_3^{2-} \) from \( \text{K}_2\text{CO}_3 \) shifts the \( \text{ZnCO}_3 \) equilibrium left, decreasing solubility. Less soluble than pure water.

Step 3: Analyze \( 0.10 \, \text{M} \, \text{KNO}_3 \)

\( \text{KNO}_3 \) dissociates into \( \text{K}^+ \) and \( \text{NO}_3^- \), no common ions with \( \text{ZnCO}_3 \). Also, \( \text{KNO}_3 \) is a neutral salt, so no hydrolysis affecting \( \text{Zn}^{2+} \) or \( \text{CO}_3^{2-} \). Solubility similar to pure water.

Step 4: Analyze \( 0.10 \, \text{M} \, \text{NH}_4\text{CH}_3\text{COO} \)

\( \text{NH}_4^+ \) hydrolyzes: \( \text{NH}_4^+ + \text{H}_2\text{O}
ightleftharpoons \text{NH}_3 + \text{H}_3\text{O}^+ \), and \( \text{CH}_3\text{COO}^- \) hydrolyzes: \( \text{CH}_3\text{COO}^- + \text{H}_2\text{O}
ightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^- \). The \( \text{H}_3\text{O}^+ \) from \( \text{NH}_4^+ \) hydrolysis reacts with \( \text{CO}_3^{2-} \) (from \( \text{ZnCO}_3 \) dissociation): \( \text{CO}_3^{2-} + \text{H}_3\text{O}^+
ightleftharpoons \text{HCO}_3^- + \text{H}_2\text{O} \), shifting \( \text{ZnCO}_3 \) equilibrium right, increasing solubility. More soluble than pure water.

Answer:

  • \( 0.10 \, \text{M} \, \text{Zn(NO}_3\text{)}_2 \): Less soluble than in pure water.
  • \( 0.10 \, \text{M} \, \text{K}_2\text{CO}_3 \): Less soluble than in pure water.
  • \( 0.10 \, \text{M} \, \text{KNO}_3 \): Similar solubility as in pure water.
  • \( 0.10 \, \text{M} \, \text{NH}_4\text{CH}_3\text{COO} \): More soluble than in pure water.