Question

use the naming rules to type the names of each covalent compound below:
h₂o
?
n₂s₄
?
co
?
so₃
?

Explanation:

Step1: Name \( \ce{H_2O} \)

Covalent compound naming uses prefixes (mono-, di-, tri-, etc.) for the number of atoms. For \( \ce{H_2O} \), the first element is hydrogen (H) with 2 atoms (prefix "di-"), but hydrogen is an exception where "mono-" is omitted for the first element if there's 1, but here 2 H: "dihydrogen", and oxygen (O) with 1 atom: "monoxide". So \( \ce{H_2O} \) is dihydrogen monoxide (commonly known as water, but by covalent naming rules: dihydrogen monoxide).

Step2: Name \( \ce{N_2S_4} \)

First element: nitrogen (N) with 2 atoms: "dinitrogen". Second element: sulfur (S) with 4 atoms: "tetrasulfide" (prefix "tetra-"). So \( \ce{N_2S_4} \) is dinitrogen tetrasulfide.

Step3: Name \( \ce{CO} \)

First element: carbon (C) with 1 atom: "carbon" (no prefix for 1 on first element). Second element: oxygen (O) with 1 atom: "monoxide" (prefix "mono-"). So \( \ce{CO} \) is carbon monoxide.

Step4: Name \( \ce{SO_3} \)

First element: sulfur (S) with 1 atom: "sulfur". Second element: oxygen (O) with 3 atoms: "trioxide" (prefix "tri-"). So \( \ce{SO_3} \) is sulfur trioxide.

Answer:

• \( \ce{H_2O} \): Dihydrogen Monoxide (or Water)
• \( \ce{N_2S_4} \): Dinitrogen Tetrasulfide
• \( \ce{CO} \): Carbon Monoxide
• \( \ce{SO_3} \): Sulfur Trioxide