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QUESTION IMAGE

use the example: if \\(\\text{h}^+ = 0.001\\text{ m}\\), then \\(\\text…

Question

use the example: if \\(\text{h}^+ = 0.001\text{ m}\\), then \\(\text{ph} = -\log(\text{h}^+) = \square\\).

3 2 1 0

Explanation:

Express concentration in scientific notation

$$ [\text{H}^+] = 0.001\text{ M} = 10^{-3}\text{ M} $$

Calculate pH using logarithmic definition

$$ \text{pH} = -\log_{10}(10^{-3}) = -(-3) = 3 $$

Answer:

Use the example: If \([\text{H}^+] = 0.001\text{ M}\), then \(\text{pH} = -\log([\text{H}^+]) =\) <blank>3</blank>.