Question

under certain conditions, the substances sulfur dioxide and oxygen combine to form sulfur trioxide. if 26.0 grams of sulfur dioxide and 6.5 grams of oxygen combine to form sulfur trioxide, how many grams of sulfur trioxide must form? mass = 19 g

Explanation:

Step1: Write the chemical reaction equation

The reaction is \(2SO_{2}+O_{2}
ightarrow 2SO_{3}\). According to the law of conservation of mass, the total mass of reactants equals the mass of products.

Step2: Calculate the mass of sulfur trioxide

The mass of reactants is the sum of the mass of sulfur - dioxide and oxygen. Given \(m_{SO_{2}} = 26.0\ g\) and \(m_{O_{2}}=6.5\ g\). Then \(m_{products}=m_{SO_{2}} + m_{O_{2}}\).

$$m_{SO_{3}}=26.0\ g + 6.5\ g=32.5\ g$$

Answer:

32.5 g