Question

two miscible liquids were mixed to the point of saturation. it was found that there was 25.00 ml of liquid a in every 350.00 ml of the solution.

1. what is the % v/v?

% v/v = \frac{\\_\\_1\\_\\_\text{ ml a}}{\\_\\_3\\_\\_\text{ ml soln}}100\\% = \\_\\_2\\_\\_\\%

1. how many ml of liquid a are in 25.00 ml of the solution? (dont use % here, use actual numbers)

(\\_\\_5\\_\\_\text{ ml soln})(\frac{\\_\\_4\\_\\_\text{ ml a}}{\\_\\_7\\_\\_\text{ ml soln}})=\\_\\_6\\_\\_\text{ ml a}
a. 36.00 b. 5.00 c. 31.00 d. 150.0 e. 12 f. 350.00
g. 100.0 h. 2.4×10⁻² i. 1.2×10⁻³ j. 1.786 k. 7.143 l. 25.00
m. 7.500 n. 125.0 o. 500.0 p. 15.00 q. 185.00 r. 444.44
s. 2.00×10³ t. 20.67 u. 0.500 v. 499.5 w. 15 x. 33.33
y. 1.00×10⁵ z. 10.0 aa. 1.00 bb. 10⁶ cc. 6.00
dd. 6.00×10⁻⁵ ee. 6.00×10⁶ ff. 20.0 gg. 200 hh. 1.20×10⁶
ii. 60 jj. 0.100 kk. 4.00 ll. 10³ mm. 0.0667 nn. 66.7

Explanation:

Step1: Calculate \(\%v/v\)

The formula for \(\%v/v=\frac{\text{Volume of solute (A)}}{\text{Volume of solution}}\times100\%\). Here, volume of solute (A) is \(25.00\) mL and volume of solution is \(350.00\) mL.
\(\%v/v=\frac{25.00}{350.00}\times100\%\)

Step2: Simplify the \(\%v/v\) calculation

\(\frac{25.00}{350.00}\times100\%=\frac{2500}{350.00}\% \approx 7.143\%\)

Step3: Calculate volume of A in \(25.00\) mL solution

We use the proportion \(\frac{\text{Volume of A}_1}{\text{Volume of solution}_1}=\frac{\text{Volume of A}_2}{\text{Volume of solution}_2}\). Let \(\text{Volume of A}_1 = 25.00\) mL, \(\text{Volume of solution}_1=350.00\) mL and \(\text{Volume of solution}_2 = 25.00\) mL. Then \(\text{Volume of A}_2=\frac{25.00}{350.00}\times25.00\) mL

Answer:

1. \(1 = 25.00\), \(2=7.143\), \(3 = 350.00\)
2. \(4 = 25.00\), \(5=25.00\), \(6\approx1.786\), \(7 = 350.00\) (where \(1.786\) is from \(\frac{25.00\times25.00}{350.00}\approx1.786\))