Question

there are 2 moles of k in one mole of k₂co₃. how many atoms of k are present in one mole of k₂co₃? 6.02×10²³ atoms 1.20×10²⁴ atoms 1.8×10²⁴ atoms 1.8×10²³ atoms

Explanation:

Step1: Recall Avogadro's number

Avogadro's number \(N_A = 6.02\times10^{23}\text{ atoms/mol}\).

Step2: Calculate the number of K atoms

Given there are 2 moles of K in 1 mole of \(K_2CO_3\).
The number of K atoms \(n = 2\space mol\times6.02\times 10^{23}\space\text{atoms/mol}\)

$$n=1.204\times 10^{24}\space\text{atoms}\approx1.20\times 10^{24}\space\text{atoms}$$

Answer:

\(1.20\times 10^{24}\space\text{atoms}\) (the second option)