Question

the solubility in water of lonic compound x is measured and found to be 0.646 g/ml at 20. °c. calculate the volume of a saturated solution of x in water that would contain 24.0 g of x at this temperature. be sure your answer has the correct unit symbol and number of significant digits.

Explanation:

Step1: Set up the proportion

Let \( V \) be the volume of the saturated solution. We know that solubility \( S=\frac{m}{V} \), where \( S = 0.646\frac{g}{mL} \) and \( m = 24.0g \). Rearranging for \( V \), we have \( V=\frac{m}{S} \).

Step2: Substitute the values

Substitute \( m = 24.0g \) and \( S=0.646\frac{g}{mL} \) into the formula \( V=\frac{24.0g}{0.646\frac{g}{mL}} \).

Step3: Calculate the volume

\( V=\frac{24.0}{0.646}mL\approx37.2mL \) (using significant - digit rules: 24.0 has 3 significant digits and 0.646 has 3 significant digits, so the result should have 3 significant digits).

Answer:

\( 37.2mL \)