Question

sn
express your answer in condensed form in order of increasing orbital energy as a
string without blank space between orbitals. for example, he2s²2p² should be
entered as he2s^22p^2.

Explanation:

Step1: Determine the atomic number of Sn

Tin (Sn) has an atomic number of 50.

Step2: Find the noble gas core

The noble gas before Sn is Kr (atomic number 36).

Step3: Write the remaining electron configuration

After [Kr], we have 14 electrons left. The configuration is \(4d^{10}5s^{2}5p^{2}\)

Answer:

[Kr]4d^105s^25p^2