Question

the skeleton equation representing the neutralization of aluminum hydroxide with hydrochloric acid is al(oh)3 + hcl ------> alcl3 + h2o. the coefficient of hcl in the balanced equation is
1
3
6
7
how many grams are there in 7.63 x 10^24 neon gas particles?
4.59 x 10^48g
50.70 g
255.6g
1.91 x 10^24

Explanation:

First Sub - Question (Balancing Chemical Equation)

Step 1: Balance Al atoms

On the left side, we have 1 Al atom in $\ce{Al(OH)3}$, and on the right side, we have 1 Al atom in $\ce{AlCl3}$. So Al atoms are balanced.

Step 2: Balance Cl atoms

On the right side, we have 3 Cl atoms in $\ce{AlCl3}$. On the left side, we have 1 Cl atom in $\ce{HCl}$. So we need to put a coefficient of 3 in front of $\ce{HCl}$ to balance Cl atoms? Wait, no, let's check O and H atoms too. Wait, let's do it properly. The unbalanced equation is $\ce{Al(OH)3 + HCl -> AlCl3 + H2O}$.
First, balance Cl: $\ce{Al(OH)3 + 3HCl -> AlCl3 + H2O}$ (now Cl is balanced: 3 on left, 3 on right).
Now balance O: On left, we have 3 O atoms in $\ce{Al(OH)3}$. On right, we have 1 O atom in $\ce{H2O}$. So we need 3 $\ce{H2O}$ molecules. So now the equation is $\ce{Al(OH)3 + 3HCl -> AlCl3 + 3H2O}$.
Now check H: On left, in $\ce{Al(OH)3}$ we have 3 H atoms, and in 3 $\ce{HCl}$ we have 3 H atoms, total 6 H atoms. On right, in 3 $\ce{H2O}$ we have 6 H atoms. O: 3 on left, 3 on right. Al: 1 on left, 1 on right. Cl: 3 on left, 3 on right. So the balanced equation is $\ce{Al(OH)3 + 3HCl = AlCl3 + 3H2O}$. So the coefficient of HCl is 3? Wait, no, wait, let's re - check. Wait, maybe I made a mistake. Wait, $\ce{Al(OH)3}$ has 3 OH groups. Each OH has 1 O and 1 H. So for O: 3 O on left. For H in $\ce{Al(OH)3}$: 3 H, and in HCl: x H. On the right, in $\ce{H2O}$: y H and y O. So let's set up equations:
Al: 1 = 1 (balanced)
Cl: x = 3 (from $\ce{AlCl3}$)
O: 3 = y
H: 3 + x = 2y
Substitute x = 3 and y = 3 into H equation: 3+3 = 2*3 → 6 = 6. So yes, x = 3. So the coefficient of HCl is 3? Wait, but wait, the options have 3 as an option. Wait, but let's do it again. The unbalanced equation: $\ce{Al(OH)3 + HCl -> AlCl3 + H2O}$
Balance Cl: $\ce{Al(OH)3 + 3HCl -> AlCl3 + H2O}$ (Cl: 3 on left, 3 on right)
Now balance O: $\ce{Al(OH)3}$ has 3 O. So $\ce{H2O}$ must have 3 O, so coefficient of $\ce{H2O}$ is 3. Now the equation is $\ce{Al(OH)3 + 3HCl -> AlCl3 + 3H2O}$
Now check H: Left side: 3 (from $\ce{Al(OH)3}$) + 3 (from 3 HCl) = 6. Right side: 2*3 (from 3 $\ce{H2O}$) = 6. So it's balanced. So the coefficient of HCl is 3.

Step 3: Conclusion

After balancing the chemical equation $\ce{Al(OH)3 + 3HCl = AlCl3 + 3H2O}$, the coefficient of HCl is 3.

Step 1: Calculate moles of Ne

We know that 1 mole of any substance contains $6.022\times10^{23}$ particles (Avogadro's number). So the number of moles ($n$) of Ne is given by $n=\frac{N}{N_A}$, where $N = 7.63\times10^{24}$ (number of Ne particles) and $N_A=6.022\times10^{23}\ \text{particles/mol}$.
$n=\frac{7.63\times10^{24}}{6.022\times10^{23}}\approx12.67\ \text{mol}$

Step 2: Calculate mass of Ne

The molar mass of Ne (M) is approximately 20.18 g/mol. The mass ($m$) is given by $m = n\times M$.
$m=12.67\ \text{mol}\times20.18\ \text{g/mol}\approx255.6\ \text{g}$

Answer:

3 (the option with 3)

Second Sub - Question (Moles and Mass of Neon)