Question

6 select the correct empirical formula for the following molecule: na₂s₂o₆
options: na₂s₂o₆, naso₃, na₂s₂o₃, naso

Explanation:

Step1: Recall empirical formula definition

Empirical formula is the simplest whole - number ratio of atoms in a compound. For the compound \(Na_2S_2O_6\), we need to find the greatest common divisor (GCD) of the subscripts 2, 2, and 6.
The GCD of 2, 2, and 6 is 2.

Step2: Divide subscripts by GCD

Divide each subscript in \(Na_2S_2O_6\) by 2.
For Na: \(\frac{2}{2}=1\)
For S: \(\frac{2}{2}=1\)
For O: \(\frac{6}{2}=3\)
So the empirical formula is \(NaSO_3\). Wait, no, wait. Wait, the original formula is \(Na_2S_2O_6\)? Wait, maybe I misread. Wait, the options: let's check again. Wait, maybe the original molecule is \(Na_2S_2O_6\)? Wait, no, the options have \(Na_2S_2O_3\), \(NaSO_3\), \(Na_2S_2O_6\) (no, wait the first option is \(Na_2S_2O_{12}\)? No, maybe the original molecule is \(Na_2S_2O_6\). Wait, no, let's recalculate. Wait, GCD of 2, 2, 6: factors of 2 are 1,2; factors of 2 are 1,2; factors of 6 are 1,2,3,6. So GCD is 2. So dividing 2 (Na), 2 (S), 6 (O) by 2 gives Na:1, S:1, O:3. So empirical formula is \(NaSO_3\). But wait, the options: one of the options is \(NaSO_3\)? Wait, the third option is \(Na_2S_2O_3\), second is \(NaSO_3\), fourth is \(NaSO\). Wait, maybe I made a mistake. Wait, maybe the original molecule is \(Na_2S_2O_6\), and we need to simplify. Wait, 2,2,6: GCD is 2. So 2/2 = 1 (Na), 2/2 = 1 (S), 6/2 = 3 (O). So empirical formula is \(NaSO_3\), which is one of the options (the second option).

Answer:

B. \(NaSO_3\) (assuming the second option is labeled B, if the options are labeled as A: \(Na_2S_2O_{12}\), B: \(NaSO_3\), C: \(Na_2S_2O_3\), D: \(NaSO\))