Question

se
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s²2p² should be entered as he2s^22p^2.

Explanation:

Step1: Determine the atomic number of Se

Selenium (Se) has an atomic number of 34.

Step2: Find the noble gas core

The noble gas before Se is Ar (atomic number 18).

Step3: Fill the remaining electrons

After [Ar], we have 34 - 18 = 16 electrons. The filling order is \(4s\), \(3d\), \(4p\). \(4s\) can hold 2 electrons, \(3d\) can hold 10 electrons, and \(4p\) can hold 6 electrons. But we have 16 electrons. So, \(4s^{2}3d^{10}4p^{4}\)

Answer:

[Ar]4s^23d^104p^4